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백준 소스코드 [C++] 2143 두 배열의 합

Hani_Levenshtein 2021. 3. 4. 14:19

www.acmicpc.net/problem/2143

 

2143번: 두 배열의 합

첫째 줄에 T(-1,000,000,000 ≤ T ≤ 1,000,000,000)가 주어진다. 다음 줄에는 n(1 ≤ n ≤ 1,000)이 주어지고, 그 다음 줄에 n개의 정수로 A[1], …, A[n]이 주어진다. 다음 줄에는 m(1≤m≤1,000)이 주어지고, 그 다

www.acmicpc.net

백준 소스코드 [C++] 2143 두 배열의 합

#include <iostream>
#include <algorithm>
#include <queue>
#include <string.h>
#include <limits.h>
#include <vector>
#include <math.h>
#include <stack>
#include <bitset>
#include <string>
#include <set>
#include <sstream>
#define all(v) v.begin(), v.end()
#define pii pair<int,int>
#define make_unique(v) v.erase(unique(v.begin(), v.end()), v.end())
typedef long long ll;
using namespace std;

int inDegree[10001], time[10001], accumulatedTime[10001];
queue<int> q;
vector<int> graph[10001];

void topologicalSort() {

	while (q.empty()!=true) {
		int here = q.front(); 
		q.pop();
		for (auto next : graph[here]) {
			accumulatedTime[next] = max(accumulatedTime[next], accumulatedTime[here] + time[next]);
			if (--inDegree[next] == 0) q.push(next);
		}
	}
}

int main() {
	ios_base::sync_with_stdio(false);
	cin.tie(NULL);
	int t;cin >> t;
	int n, m;
	cin >> n;
	vector<int> a(n);
	vector<int> sumA;
	for (int i = 0;i < n;i++) cin >> a[i];
	for (int i = 0;i < n;i++) {
		int sum = 0;
		for (int j = i;j < n;j++) {
			sum += a[j];
			sumA.push_back(sum);
		}
	}

	cin >> m;
	vector<int> b(m);
	vector<int> sumB;
	for (int i = 0;i < m;i++) cin >> b[i];
	for (int i = 0;i < m;i++) {
		int sum = 0;
		for (int j = i;j < m;j++) {
			sum += b[j];
			sumB.push_back(sum);
		}
	}

	sort(all(sumA)); sort(all(sumB));
	int pA = 0, pB = (int)sumB.size() - 1;
	ll res = 0;
	while (pA <= (int)sumA.size() - 1 && 0 <= pB) {

		if (sumA[pA] + sumB[pB] < t) pA++;
		else if (sumA[pA] + sumB[pB] > t) pB--;
		else {
			ll cntA = 1, cntB = 1;
			while (pA + 1 <= (int)sumA.size() - 1 && sumA[pA] == sumA[pA + 1])
			{
				cntA++, pA++;
			}
			while (0 <= pB - 1 && sumB[pB] == sumB[pB - 1])
			{
				cntB++, pB--;
			}
			res += cntA * cntB;
			pA++, pB--;
		}
	}
	cout << res;
	return 0;
}
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