백준
백준 소스코드 [C++] 2150 Strongly Connected Component
Hani_Levenshtein
2021. 4. 15. 08:37
2150번: Strongly Connected Component
첫째 줄에 두 정수 V(1 ≤ V ≤ 10,000), E(1 ≤ E ≤ 100,000)가 주어진다. 이는 그래프가 V개의 정점과 E개의 간선으로 이루어져 있다는 의미이다. 다음 E개의 줄에는 간선에 대한 정보를 나타내는 두 정
www.acmicpc.net
백준 소스코드 [C++] 2150 Strongly Connected Component
#include <iostream>
#include <algorithm>
#include <queue>
#include <string.h>
#include <limits.h>
#include <vector>
#include <math.h>
#include <stack>
#include <bitset>
#include <string>
#include <set>
#include <map>
#include <unordered_map>
#include <sstream>
#include <cstdlib>
#define all(v) v.begin(), v.end()
#define pii pair<int, int>
#define pli pair<ll, int>
#define make_unique(v) sort(all(v)), v.erase(unique(all(v), v.end())
typedef long long ll;
using namespace std;
vector<vector<int>> graph, reverseGraph;
bool chk[10001];
int SCC[10001];
vector<int> arr;
int n, m,a,b,total = 0;
void dfs(int here){
chk[here] = true;
for(auto there : graph[here]) if(!chk[there]) dfs(there);
arr.push_back(here);
}
void reversedfs(int here, int ith){
chk[here] = true;
SCC[here] = ith;
for(auto there : reverseGraph[here]) if(!chk[there]) reversedfs(there, ith);
}
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cin >> n >> m;
graph.resize(n+1);
reverseGraph.resize(n+1);
for(int i=0; i<m; i++){
cin >> a >> b;
graph[a].push_back(b);
reverseGraph[b].push_back(a);
}
for(int i=1; i<=n; i++) if(!chk[i]) dfs(i);
memset(chk, false, sizeof(chk));
for(int here = (int)arr.size()-1; 0<=here; here--)
if(!chk[arr[here]]) reversedfs(arr[here], ++total);
cout << total << '\n';
vector<vector<int>> result(total);
for(int i=1; i<=n; i++) result[SCC[i]-1].push_back(i);
for (int i = 0; i < total; i++) sort(all(result[i]));
sort(all(result));
for (auto here : result){
for (auto there : here) cout << there << ' ';
cout << "-1\n";
}
return 0;
}